Answer :
to find the midpoint if you have the points
(x,y) and (z,t) and you wnat to finnd the midpoint you do
midpoint=([tex] \frac{x+z}{2} , \frac{y+t}{2} [/tex])
so
1. (4,7) and (-3,11)
midpoint=([tex] \frac{4-3}{2} , \frac{7+11}{2} [/tex] )=(1/2,9)
2. (-8,3) ad (-6,-3)
midpoint=([tex] \frac{-8-6}{2} , \frac{3+11}{2} [/tex])=(-7,7)
3. (-8,5) and (-3,-5)
(-3,-5)=([tex] \frac{-8+x}{2} , \frac{5+y}{2} [/tex])
so
-3=[tex] \frac{-8+x}{2} [/tex]
-6=-8+x
2=x
-5=[tex] \frac{5+y}{2} [/tex]
-10=5+y
-15=y
B=(2,-15)
4. (9,-2) and (5,7)
(5,7)=([tex] \frac{9+x}{2} , \frac{-2+y}{2} [/tex])
5=[tex] \frac{9+x}{2} [/tex]
10=9+x
1=x
7=[tex] \frac{-2+y}{2} [/tex]
14=-2+y
16=y
A=(1,16)
1. M=(1/2,9)
2. M=(-7,7)
3.B=(2,-15)
4. A=(1,16)
(x,y) and (z,t) and you wnat to finnd the midpoint you do
midpoint=([tex] \frac{x+z}{2} , \frac{y+t}{2} [/tex])
so
1. (4,7) and (-3,11)
midpoint=([tex] \frac{4-3}{2} , \frac{7+11}{2} [/tex] )=(1/2,9)
2. (-8,3) ad (-6,-3)
midpoint=([tex] \frac{-8-6}{2} , \frac{3+11}{2} [/tex])=(-7,7)
3. (-8,5) and (-3,-5)
(-3,-5)=([tex] \frac{-8+x}{2} , \frac{5+y}{2} [/tex])
so
-3=[tex] \frac{-8+x}{2} [/tex]
-6=-8+x
2=x
-5=[tex] \frac{5+y}{2} [/tex]
-10=5+y
-15=y
B=(2,-15)
4. (9,-2) and (5,7)
(5,7)=([tex] \frac{9+x}{2} , \frac{-2+y}{2} [/tex])
5=[tex] \frac{9+x}{2} [/tex]
10=9+x
1=x
7=[tex] \frac{-2+y}{2} [/tex]
14=-2+y
16=y
A=(1,16)
1. M=(1/2,9)
2. M=(-7,7)
3.B=(2,-15)
4. A=(1,16)