A ship sails 50 kilometers 60 degrees north of east. it then turns 110 degrees to the west, giving it a new heading of 10 degrees north of west. after sailing another 10 kilometers, how far is the boat (in kilometers) from where it started?

Answer :

(20sin (-30) , 20cos (-30)) + ( 0,20,0) = (10, 10√3 + 20)  

magnitude = 38.64 km (4sf)

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