Answered

What is the magnitude of the orbital velocity of the planet mercury (orbit radius =5.79× 10 7 km , orbital period = 88.0 days)?

Answer :

The orbital speed of the planet mercury can be calculated by the formula,

[tex]v=\frac{2\pi R}{T}[/tex]

Here, R is the orbital radius and T is the orbital time.

Given [tex]R=5.79\times10^{7} km[/tex] and [tex]T =88 days[/tex] (in second [tex]T= 88 \times 24 \times 60\times 60=88\times86400 s[/tex]

Substituting these values in above formula we get,

[tex]v=2\times\frac{22}{7} \times\frac{5.79\times10^{7} }{88\times86400}[/tex]

[tex]v=47.89 km/s\simeq 47.9 km/s[/tex]

Thus, the orbital velocity of the planet mercury is 47.9 km/s


Other Questions