Answered

A gasoline engine operates at a temperature of 270°C and exhausts at 180°C. Calculate the maximum efficiency of this engine. (Note that the Celsius scale is used.) 83.0 % 33.3 % 17.0 % 16.6 %

Answer :

osprey2015

(1-180/270) x 100 = efficiency

1/3=33pc

Answer:

Efficiency of gasoline engine is 16.6 %

Explanation:

It is given that,

A gasoline engine operates at a temperature of, T₁ = 270 C = (270 + 273) K = 543 K

It exhausts at a temperature, T₂ = 180 C = (180 + 273) K = 453 K

The efficiency of this engine is given by :

[tex]\eta=(1-\dfrac{T_2}{T_1})\times 100[/tex]

[tex]\eta=(1-\dfrac{453\ K}{543\ K})\times 100[/tex]

[tex]\eta=16.57\%[/tex]

or

[tex]\eta=16.6\%[/tex]

So, the efficiency of this engine is 16.6 %.Hence, the correct option is (d).

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