Answer :
consider the east-west direction along the x-direction and north-south direction along the y-axis
a)
x₁ = initial position = 40 i + 0 j
x₂ = final position = 0 i + 40 j
displacement is given as
Δx = x₂ - x₁ = (0 i + 40 j) - (40 i + 0 j ) = - 40 i + 40 j
magnitude : sqrt((- 40)² + (40)²) = 56.6 m
b)
direction : 180 - tan⁻¹(40/40) = 135 deg counterclockwise from east
c)
average velocity is given as
average velocity = displacemen/time
average velocity = (- 40 i + 40 j )/30 = - 1.33 i + 1.33 j
magnitude : sqrt((- 1.33)² + (1.33)²) = 1.88 m/s
d)
direction : direction : 180 - tan⁻¹(1.33/1.33) = 135 deg counterclockwise from east
e)
v₁ = initial velocity = - 10 j
v₂ = final velocity = 10 i
average acceleration is given as
a = (v₂ - v₁)/t = (10 i - 10 j)/30 = 0.33 i - 0.33 j
magnitude : sqrt((0.33)² + (- 0.33)²) = 0.47 m/s
f)
direction : direction : 360 - tan⁻¹(0.33/0.33) = 315 counterclockwise from east