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What is the equation for a geometric sequence with a first term of 2 and a second term of −8?
an = 2(8)n − 1
an = 2(−8)n − 1
an = 2(4)n − 1
an = 2(−4)n − 1

Answer :

wegnerkolmp2741o

Answer:

an = 2 (−4)^ (n − 1)

Step-by-step explanation:

A geomteric sequence is in the form

an = a1 (r)^(n-1)

a1 =2  and

a2 = -8

-8 = 2 r ^ (2-1)

Divide each side by 2

-4 = r ^1

r = -4

an = 2 (-4) ^ (n-1)

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