Find the equation of the line that passes through the point (-3,-4) and this parallel to the line that passes through the points (-5,1) and (7,-3)

Answer :

Answer:

y = - [tex]\frac{1}{3}[/tex] x - 5

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y-intercept )

To calculate m use the gradient formula

m = ( y₂ - y₁ ) / ( x₂ - x₁ )

with (x₁, y₁ ) = (-5,1) and (x₂, y₂ ) = (7, - 3)

m = [tex]\frac{-3-1}{7+5}[/tex] = [tex]\frac{-4}{12}[/tex] = - [tex]\frac{1}{3}[/tex]

• Parallel lines have equal slopes

hence [tex]m_{perpendicular}[/tex] = - [tex]\frac{1}{3}[/tex], thus

y = - [tex]\frac{1}{3}[/tex] x + c ← is the partial equation

T find c substitute (- 3, - 4) into the partial equation

- 4 = 1 + c ⇒ c = - 4 - 1 = - 5

y = - [tex]\frac{1}{3}[/tex] x - 5 ← equation of parallel line



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