#7
Given that an electron revolves in a circle and the essential centripetal force is given as
[tex]F = 4.60 \times 10^{-14}N[/tex]
now we need to find its speed
so we know that this force is given as
[tex]F = \frac{mv^2}{R}[/tex]
[tex]4.60 \times 10^{-14} = \frac{9.11 \times 10^{-31} v^2}{2 \times 10^{-2}}[/tex]
[tex]v^2 = 1.01 \times 10^{15}[/tex]
[tex]v = 3.18 \times 10^7 m/s[/tex]
#8
Here the force due to earth on satellite is the centripetal force to revolve around earth
so we can say that force due to earth is given as
[tex]F = \frac{mv^2}{R}[/tex]
we know that
[tex]m = 2.7 \times 10^3 kg[/tex]
[tex]v = 4.7 \times 10^3 m/s[/tex]
[tex]R = 1.8 \times 10^7 m[/tex]
now from above equation we have
[tex]F = \frac{(2.7 \times 10^3)(4.7 \times 10^3)^2}{1.8 \times 10^7}[/tex]
[tex]F = 3313.5 N[/tex]