keldoge
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What is the refractive index of a diamond if the angle of refraction in a diamond is 21.10° and the angle of incidence of light from air on the diamond is 60.45°? The refractive index of air is 1.00.

Answer :

Histrionicus

Given data:

Angle of incidence of light (i) = 60.45°,

Angle of refraction of light (r) = 21.10°,,

determine,

                Refractive index of the diamond(n) = ?

Refractive index (n) is the measure of bending of the light ray. It is defined as the ratio of "sine of the angle of incidence (i) to the sine of the angle of refraction(r)". Refractive index is also known as index of refraction.

Mathematically,

                       refractive index (n) = sin i/sin r

                                                       = sin (60.45°) / sin (21.10°)

                                                       = 2.41

The refractive index of the light is 2.41


tabb69

Answer:

n2= 2.42

Explanation:

known values

angle of incidence (θ1) = 60.45°.

angle of refraction (θ2) = 21.10°

refractive index of air (n1) = 1.00

unknown value: refractive index of a diamond (n2)

Snell’s law equation: n1 sin θ1 = n2 sin θ2

for light traveling from air to a diamond

Substitute known values in this equation to get

(1)(sin 60.45°) = (n2)(sin 21.10°)

n2 = 2.42

The refractive index of a diamond is 2.42.

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