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Two cars are traveling on two different routes, one 43 miles longer than the other. The car traveling on the longer route travels 2 miles per hour slower than the other car and it takes it 6 hours for the trip. If the car with the shorter route takes 5 hours for its trip, find the length of each route. plz help ASAP, due tonight

Answer :

boffeemadrid

Answer:

Step-by-step explanation:

Let "s" be the the speed of the car taking   the shorter route in [tex]\frac{mi}{hr}[/tex],

Let "s-2"  the speed of the cat taking the   longer route in [tex]\frac{mi}{hr}[/tex],

Let "d" be the distance of the shorter route in miles and "d+43" be the distance of the longer route in miles.

Now, Equation for car taking the shorter route is given as:

[tex]d=s{\times}5[/tex]                      (1)

and Equation for car taking the longer route is given as:

[tex]d+43=(s-2){\times}6[/tex]               (2)

Now, substitute equation (1) in (2), we get

[tex]5s+43=6s-12[/tex]

⇒[tex]43+12=s[/tex]

⇒[tex]s=55[/tex]

Therefore, equation (1) becomes,

[tex]d=5s=5(55)=275[/tex]

Thus, the shorter route is =275 miles and the longer route is =d+43=275+43= 318 miles.

Answer:

318 and 275

Sorry for no explanation :/

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