Answer :
Answer: Dimensions of rectangle are 22 cm and 15 cm respectively.
Step-by-step explanation:
Since we have given that
Let the length of rectangle be x
Let the width of rectangle be x-7
As we know the formula for "Area of rectangle":
[tex]Area=length\times breadth\\\\330=x\times (x-7)\\\\330=x^2-7x\\\\x^2-7x-330=0\\\\x^2-22x+15x-330=0\\\\x(x-22)+15(x-22)=0\\\\(x-22)(x+15)=0\\\\x=22,-15\\\\\text{But dimension can't be in negative}\\\\x=22\ cm[/tex]
Hence, Length of rectangle = 22 cm
Width of rectangle = 22-7 = 15 cm.
Answer:
The length of rectangle is 22cm and width is 15cm.
Step-by-step explanation:
Let x is length of rectangle.
let x-7 is the width of rectangle.
Area is given .
A = 330 cm²
The formula for area of rectangle is
A = length × width
Putting above values in above equation, we have
330 = x(x-7)
330 = x²-7x
x²-7x-330 = 0
We solve above equation by factoring.
Split the middle term of above equation, we have
x²-22x+15x-330 = 0
Making two groups, we have
x(x-22)+15(x-22) = 0
Taking x-22 as common, we have
(x-22)(x+15) = 0
Applying Zero Product Propert, we have
x-22 = 0 or x+15= 0
x=22 or x=-15
Length of rectangle can not be negative.
Hence, x = 22 is true.
x-7 = 22-7=15
Then, the length of rectangle is 22cm and width is 15cm.