Two weather tracking stations are on the equator 146 miles apart. A weather balloon is located on a bearing of N 35°E from the western station and on a bearing of N 23°E from the eastern station. How far is the balloon from the western station? (2 points)

Answer :

The distance between the weather tracking station and the balloon can be

found by triangulation.

The distance from the balloon to the western station is approximately 646.4 miles

Reasons:

The given parameters are;

Distance between the two stations = 146 miles

Location of the weather balloon from the Western station = N35°E

Location of the weather balloon from the Eastern station = N23°E

The location of the station = On the equator

Required:

The distance of the balloon from the Western station

Solution:

  • The angle formed between the horizontal, and the line from the Western station to the balloon = 90° - 35° = 55°
  • The angle formed between the horizontal, and the line from the Eastern station to the balloon = 90° + 23° = 113°

The angle at the vertex of the triangle formed by the balloon and the two stations is 180° - (55 + 113)° = 12°

By sine rule, we have;

[tex]\dfrac{146}{sin(12^{\circ})} = \dfrac{Distance \ from \ balloon \ to \ western \ station}{sin(113^{\circ})}[/tex]

Therefore;

[tex]Distance \ from \ balloon \ to \ western \ station}{}=\dfrac{146}{sin(12^{\circ})} \times sin(113^{\circ}) \approx 646.4[/tex]

The distance from the balloon to the Western station is approximately 646.4 miles.

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