Write a function describing the relationship of the given variables.


A
varies directly with the square root of
r
and when
r
=
16
,
A
=
40



A
=

Answer :

Ashraf82

Answer:

The function is A = 10√r

Step-by-step explanation:

* Lets explain the meaning of direct variation

- The direct variation is a mathematical relationship between two

  variables that can be expressed by an equation in which one

  variable is equal to a constant times the other

- If Y is in direct variation with x (y ∝ x), then y = kx, where k is the

 constant of variation

* Now lets solve the problem

# A is varies directly with the square root of r

- Change the statement above to a mathematical relation

∴ A ∝ √r

- Chang the relation to a function by using a constant k

∴ A = k√r

- To find the value of the constant of variation k substitute A and r

 by the given values

∵ r = 16 when A = 40

∵ A = k√r

∴ 40 = k√16 ⇒ simplify the square root

∴ 40 = 4k ⇒ divide both sides by 4 to find the value of k

∴ 10 = k

- The value of the constant of variation is 10

∴ The function describing the relationship of A and r is A = 10√r

Answer:

A = 10[tex]\sqrt{r}[/tex]

Step-by-step explanation:

Given A varies directly with the square root of r then the equation relating them is

A = k[tex]\sqrt{r}[/tex] ← k is the constant of variation

To find k use the condition r = 16 , A = 40

k = [tex]\frac{A}{\sqrt{r} }[/tex] = [tex]\frac{40}{\sqrt{16} }[/tex] = [tex]\frac{40}{4}[/tex] = 10

A = 10[tex]\sqrt{r}[/tex] ← equation of variation

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