Rewrite the inequality as
[tex]-2y<3(x-2) \iff -2y < 3x-6 \iff y>-\dfrac{3}{2}x+3[/tex]
First, we have to draw the graph of the equation
[tex]y=-\dfrac{3}{2}x+3[/tex]
To do so, we choose a couple of x values, and we deduce the y values to find two points lying on the line:
[tex]x = 0 \implies y = 3\\ x=2 \implies y=0[/tex]
This means that you can draw the points [tex](0,3),\ (2,0)[/tex], connect them, and you have the line.
Now, since the line is composed by the point where y is exactly -3/2x+3, and we want the points where y is greater than -3/2x+3, we are interested in all the points on the plane that are above the line.