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Suppose you wanted to dissolve 109 g of sodium carbonate in enough water to make 6.00 L of solution. What is the molarity of this solution?

Answer :

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Molarity

a. Na2CO3
                Molar mass = 106 g/mol
    n= 109 g / (106 g/mol) = 1.028 mol

b. 6.00L

c. M=n/V
    M = 1.028 mol / 6.00 L
    M= 0.1713 mol / L

Answer: The molarity of the sodium carbonate solution is 0.1713 mol/L

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