Answer :
Answer:
2313
Step-by-step explanation:
A = P(1+r)^t
where A is the final amount, P is the initial amount, r is the rate, and t is time.
Here, P = 1000, r = 0.15, and t = 6.
A = 1000(1.15)^6
A ≈ 2313
Number of bacteria after 6 days is 2313
Step-by-step explanation:
Population after n days is given by
[tex]P_n=P_0(1+r)^n[/tex]
Initial population, P₀ = 1000
Increase rate, r = 15 % = 0.15
Number of days, n = 6
Substituting
[tex]P_n=P_0(1+r)^n\\\\P_6=1000(1+0.15)^6\\\\P_6=1000(1.15)^6\\\\P_6=1000\times 2.313\\\\P_6=2313[/tex]
Number of bacteria after 6 days = 2313