Answer: [tex]\bold{b)\quad \dfrac{17}{36}}[/tex]
Step-by-step explanation:
[tex].\quad \dfrac{1}{6}\bigg(2\dfrac{1}{3}-\dfrac{3}{4}\bigg)+\dfrac{5}{24}\\\\\\=\dfrac{1}{6}\bigg(\dfrac{7}{3}-\dfrac{3}{4}\bigg)+\dfrac{5}{24}\\\\\\=\dfrac{1}{6}\bigg(\dfrac{28}{12}-\dfrac{9}{12}\bigg)+\dfrac{5}{24}\\\\\\=\dfrac{1}{6}\bigg(\dfrac{19}{12}\bigg)+\dfrac{5}{24}\\\\\\=\dfrac{19}{72}+\dfrac{5}{24}\\\\\\=\dfrac{19}{72}+\dfrac{15}{72}\\\\\\=\dfrac{34}{72}\\\\\\=\large\boxed{\dfrac{17}{36}}[/tex]
