Answer :
The force applied by the gymnast on the mat when her deceleration is 7.00 times the acceleration due to gravity is 2,781.135 N.
Given to us
Mass of the gymnast, m = 40.5 kg
deceleration, d = 7.00 times the acceleration due to gravity
What is the deceleration of the gymnast?
We know that the value of acceleration due to gravity is 9.81 m\sec². And, it is given that the deceleration is 7 times the acceleration due to gravity. therefore,
deceleration, d = 7 x g
= 7 x 9.81
= 68.67 m\sec²
What is the force exerted by the gymnast on the mat?
We know that according to the first law of motion,
[tex]\rm Force = mass \times deceleration[/tex]
Substituting the values,
[tex]\rm Force = 40.5 \times 68.67\\[/tex]
[tex]\rm= 2,781.135\ N[/tex]
Thus, the force applied by the gymnast on the mat when her deceleration is 7.00 times the acceleration due to gravity is 2,781.135 N.
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