Answer :
Answer:
Here is code in java.
import java.util.*;
class Main
{
//main method of the class
public static void main (String[] args) throws java.lang.Exception
{
try{
int m;
// scanner object to read input from user
Scanner ss=new Scanner(System.in);
System.out.println(" size of the array:");
//read the size of the array
m=ss.nextInt();
// create array of the given size
float arr[]=new float[m];
/* call function to check whether input are in the ascending sorted order or not */
Boolean res= issorted(arr,m);
// print the result
System.out.println("array in the ascending sorted order : "+res);
}catch(Exception ex){
return;}
}
// function to check whether input are in the ascending sorted order or not
public static boolean issorted(float[] arr,int n)
{
int i,j;
float d;
Boolean flag=true;
Scanner ss=new Scanner(System.in);
System.out.println("enter the elements of the array:");
// read elements of the array
for(i=0;i<n;i++)
{
arr[i]=ss.nextFloat();
}
// check elements re in the ascending order or not
for(j=0;j<n-1;j++)
{
if(arr[j]>arr[j+1])
{
flag=false;
break;
}
}
// return the result
return flag;
}
}
Explanation:
With the help of scanner class object, read the size "m" of array.Create an array of the given size. Pass array and integer into the function issorted(). Read the elements of the array and then check elements are in the ascending order or not.It will return "true" if elements are in the sorted order else it will return "false".
Output:
enter size of the array:
5
enter the elements of the array:
1 2 3 4 7
array in the ascending sorted order : true
enter size of the array:
5
enter the elements of the array:
2 4 9 3 5
array in the ascending sorted order : false