Answer :
Here is code in java.
//import package
import java.util.*;
class Solution {
// main method of class Solution
public static void main (String[] args) throws java.lang.Exception
{
try{
// create a list of Integer type
ArrayList<Integer> list = new ArrayList<Integer>();
// create an object of Scanner class to read input
Scanner s=new Scanner(System.in);
int i;
// ask for length of list
System.out.println("How many numbers in the list ? ");
int len=s.nextInt();
System.out.println("please enter "+len+" numbers: " );
// read input from user
for(i=0;i<len;i++)
{
int x=s.nextInt();
list.add(x);
}
// sort the list
Collections.sort(list);
// declare and initialize "dis" variable with max value of Integer
int dis=Integer.MAX_VALUE;
for( i=0;i<len-1;i++)
{ // find the minimum distance between list elements
int m=list.get(i+1)-list.get(i);
if(m<dis)
dis=m;
}
// print the minimum distance
System.out.println("minimum distance is:"+dis);
}catch(Exception ex){
return;}
}
}
Explanation:
Create an empty list of Integer type. Ask user to give length (n) of list.
Then read n Integer into the list.Sort the list in ascending order.Create
a variable dis and initialize it with maximum value of Integer.Then travers
the list and find the distance between two consecutive elements and store
it in a variable "m" and then compare with "dis", if value of "m" is less
than value of "dis" then update the value of "dis" with value of "m". When
the loop ends, "dis" will have minimum distance between list elements.
Output:
How many numbers in the list ?
10
please enter 10 numbers:
2
5
13
90
34
56
78
86
112
40
minimum distance is:3