Answer :
Answer:
Explanation:
The electric field due to a positive charge at a distance is given by
[tex]E = \frac{1}{4\pi \epsilon _{0}}\frac{q}{r^{2}}[/tex]
Where, q be the charge on the charged particle and r be the distance between the charged particle and the point where electric field is to be calculated.
If the medium is inserted whose dielectric constant is K , then the electric field becomes
[tex]E' = \frac{1}{4\pi \epsilon _{0}K}\frac{q}{r^{2}}[/tex]
As teh value of K is more than 1, so the value of electric field E' is less than E.
It means when the medium is inserted, the electric field becomes reduced.