Answer :
Answer:
It will take the stones 2.67s to be 25 m apart.
Explanation:
if s is the distance between the stones.
for the first stone:
s = u×t + 1/2×g×t^2
since u is the initial velocity, u = o m/s.
s1 = 1/2×g×t^2
for the second block:
s2 = 1/2×g×(t - 1.25)^2
then s1 - s2 = 25 m,
s1 - s2 = 1/2×g×t^2 - 1/2×g×(t - 1.25)^2
25 = 1/2×g×t^2 - 1/2×g×(t - 1.25)^2
50 = g×t^2 - g×(t - 1.25)^2
50/g = t^2 - (t - 1.25)^2
50/g = t^2 - (t^2 - 2.5×t + 1.5625)
50/g = 2.5×t - 1.5625
t = [50/g+1.5625]/(2.5)
= [50/(9.8)+1.5625]/(2.5)
= 2.67 s
Therefore, it will take the stones 2.67s to be 25 m apart.