Answer :
Answer:
a) frequencies of the two alleles - [tex]q=0.3, p=0.7[/tex]
b) the frequencies of the three genotypes -
[tex]p^2=0.49\\2pq=0.42\\q^2= 0.09[/tex]
Explanation:
Given,
Phenotypic frequency of albino is [tex]0.09[/tex]
Being a recessive allele, the phenotypic frequency will exits in species that have homozygous recessive genotype i,e cc
Thus , the genotypic frequency of "cc" is [tex]0.09[/tex]
As per Hardy Weinberg's equation, frequency of homozygous recessive genotype is represented by "[tex]q^{2}[/tex]"
So, the frequency of recessive allele will be "q"
[tex]q=\sqrt{q^2} \\q=\sqrt{0.09} \\q= 0.3[/tex]
Hence, as per equation [tex]p+q=1[/tex]
[tex]p=1-q\\p=1-0.3\\p=0.7[/tex]
Frequency of genotype "homozygous dominant CC" will be
[tex]p^{2} \\0.7^2\\0.49[/tex]
As per second equation of Weinberg's equillibrium-
[tex]p^{2} +2pq+q^{2} =1\\0.49+2pq+0.09=1\\2pq=0.42[/tex]
Hence,
a) frequencies of the two alleles - [tex]q=0.3, p=0.7[/tex]
b) the frequencies of the three genotypes -
[tex]p^2=0.49\\2pq=0.42\\q^2= 0.09[/tex]