Answer :
Answer:
The proportion of boxes containing less than 18oz is 0.0013
Step-by-step explanation:
A normal random variable with mean Mu = 19.2 and standard deviation sd = 0.4 is standardized with the transformation:
Z = (X - Mu) / sd = (X - 19.2) / 0.4
For a weight value of 18oz, Z = (18 - 19.2) / 0.4 = -3.00.
P (X <18) = P (Z <-3.00) = 0.0013.
The proportion of boxes containing less than 18oz is 0.0013