Answer :
Answer:
[tex]2.64\times 10^{-7} C[/tex]
Explanation:
There are two spheres name 1 and 2 and they posses the same charge, which is +q.
And they have equal mass which is 2.098 g.
The distance between these two spheres is, [tex]r=3.338 cm[/tex].
And the acceleration of each sphere is, [tex]a=269.429 m/s^{2}[/tex].
Now the coulumbian force experience by 1 sphere due to 2 sphere,
[tex]F_{21} =\frac{q^{2} }{4\pi\epsilon_{0} r^{2} }[/tex].
And also the newton force will occur due to this force,
[tex]F_{21}=ma[/tex].
Now equate the above two values of force will get,
[tex]\frac{q^{2} }{4\pi\epsilon_{0} r^{2} } =ma[/tex]
Further solve this,
[tex]q^{2}=ma4\pi \epsilon_{0} r^{2}[/tex].
Substitute all the known variables in above equation,
[tex]q^{2}=(2.098\times 10^{-3} )(269.429)(4(3.14))(8.85\times 10^{-12})(3.338\times 10^{-2})[/tex].
[tex]q=2.64\times 10^{-7} C[/tex].