Determine which of the following pairs of reactants will result in a spontaneous reaction at 25°C. None of the above pairs will react. Fe3+(aq) + Mg(s) Pb2+(aq) + Au(s) Ag+(aq) + Br⁻(aq) Li+(aq) + Cr(s)

Answer :

JannetPalos

Answer:

Only [tex]Fe^{3+}+Mg[/tex] gives spontaneous reaction.

Explanation:

A redox reaction will be spontaneous if standard reduction potential ([tex]E^{0}[/tex]) of the reaction is positive. Because it leads to negative standard gibbs free energy change ([tex]\Delta G^{0}[/tex]), which is a thermodynamic condition for spontaneity of a reaction.

[tex]E^{0}=E^{0}(reduction)-E^{0}(oxidation)[/tex]

Where [tex]E^{0}(reduction)[/tex] and [tex]E^{0}(oxidation)[/tex] represents standard reduction potential of reduction half cell and standard reduction potential of oxidation half cell.

(1) Oxidation:         [tex]Mg-2e^{-}\rightarrow Mg^{2+}[/tex] ;  [tex]E_{Mg^{2+}\mid Mg}^{0}=-2.38V[/tex]

Reduction:         [tex]Fe^{3+}+3e^{-}\rightarrow Fe[/tex] ; [tex]E_{Fe^{3+}\mid Fe}^{0}=-0.04V[/tex]

So, [tex]E^{0}=E_{Fe^{3+}\mid Fe}^{0}-E_{Mg^{2+}\mid Mg}^{0}=(-0.04+2.38)V=2.34V[/tex]

Hence this pair will give spontaneous reaction.

(2) Similarly as above, [tex]E^{0}=E_{Pb^{2+}\mid Pb}^{0}-E_{Au^{+}\mid Au}^{0}=(-0.13-1.69)V=-1.82 V[/tex]

Hence this pair will give non-spontaneous reaction.

(3) Similarly as above, [tex]E^{0}=E_{Ag^{+}\mid Ag}^{0}-E_{Br_{2}\mid Br^{-}}^{0}=(0.80-1.07)V=-0.27 V[/tex]

Hence this pair will give non-spontaneous reaction.

(4)  Similarly as above, [tex]E^{0}=E_{Li^{+}\mid Li}^{0}-E_{Cr^{3+}\mid Cr}^{0}=(-3.04+0.74)V=-2.30 V[/tex]

Hence this pair will give non-spontaneous reaction.

The Fe-Mg pair of reactants will react spontaneously without any extra activation energy (ie. thermal or light).

What are Spontaneous Reactions?

  • It is the reaction in which reactants react with each other without any extra activation energy (ie. thermal or light).
  • The standard reduction potential is positive for spontaneous reaction.

[tex]E^0 = E^0_{rd} + E^0_{ox}[/tex]

Where,

[tex]E^0[/tex] - standard reduction potential

E^0_rd - standard reduction potential of reducing reactant

E^0_ox - standard reduction potential of oxidizing reactant

For, Fe - Mg pair-

E^0_rd of Iron  = -0.04 V

E^0_ox of Mg  = -2.38 V

Put the values in the formula,

[tex]E^0 = -0.04 + (-2.38)\\\\E^0 = 2.34 \rm \ V[/tex]

Therefore, the Fe-Mg pair of reactants will react spontaneously.

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