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Points A and B have electric potentials of 330 V and 200 V , respectively. When an electron released from rest at point A arrives at point C, its kinetic energy is KA. When the electron is released from rest at point B, however, its kinetic energy when it reaches point C isKB=2KA
What is the electric potential at point C?

Answer :

Answer:265 V

Explanation:

Given Potential At points A and B is 330 V and 200 V

When an Electrons is released from rest From A to C

[tex]K_A=q(V_c-V_a)[/tex]

when an electron is released from B to reach at C

[tex]K_B=q(V_b-V_a)[/tex]

Given [tex]K_B=2K_A[/tex]

[tex]q(V_b-V_a)=2q(V_c-V_a)[/tex]

[tex]V_b-V_a=2V_c-2V_a[/tex]

[tex]V_c=\frac{V_b+V_a}{2}[/tex]

[tex]V_c=265 V[/tex]

Thus electric Potential at point C is 265 V

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