Answer :
Explanation:
Formula to calculate heat capacity is as follows.
[tex]C_{p}[/tex] = a + bT + [tex]cT^{-2}[/tex]
where, a, b and c are constants.
Their values at [tex]49.0^{o}C[/tex] are as follows.
a = [tex]68.62 \times 10^{-3}[/tex]
b = [tex]1.19 \times 10^{-5}[/tex]
c = [tex]-8.66 \times 10^{10} \times 10^{-8}[/tex]
Hence, putting the given values into the above formula as follows.
[tex]C_{p}[/tex] = a + bT + [tex]cT^{-2}[/tex]
= [tex]68.62 \times 10^{-3} + 1.19 \times 10^{-5} \times 49.0 + -8.66 \times 10^{10} \times 10^{-8} \times (49.0)^{-2}[/tex] kJ/mol K
= 14.43 kJ/mol K
Thus, we can conclude that the heat capacity of crystalline calcium carbide at 49.0[tex]^{o}C[/tex] is 14.43 kJ/mol K.