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For the following equilibrium: 3A + B = 20 If equilibrium concentrations are [A] = 1.1 M and [B] = 1.4 M, and Kc = 11.3, what is the equilibrium concentration of C? • Your answer should have two significant figures. Provide your answer below:

Answer :

Answer : The equilibrium concentration of C is 4.6 M

Solution :  Given,

Concentration of [tex]A[/tex] at equilibrium = 1.1 M

Concentration of [tex]B[/tex] at equilibrium = 1.4 M

[tex]K_c=11.3[/tex]

First we have to calculate the value of equilibrium constant.

The given equilibrium reaction is,

[tex]3A+B\rightleftharpoons 2C[/tex]

The expression of [tex]K_c[/tex] will be,

[tex]K_c=\frac{[C]^2}{[A]^3[B]}[/tex]

[tex]11.3=\frac{[C]^2}{(1.1)^3\times (1.4)}[/tex]

[tex][C]=4.6M[/tex]

Therefore, the equilibrium concentration of C is 4.6 M

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