Answer :

Answer:

C ) 1.70 g/L

Explanation:

Using ideal gas equation as:

PV=nRT

where,  

P is the pressure

V is the volume

n is the number of moles

T is the temperature  

R is Gas constant having value = 0.0821 L.atm/K.mol

Also,

Moles = mass (m) / Molar mass (M)

Density (d)  = Mass (m) / Volume (V)

So, the ideal gas equation can be written as:

PM=dRt

At STP,

Pressure = 1 atm

Temperature = 273.15 K

Molar mass of fluorine gas = 38 g/mol

Applying the equation as:

1 atm × 38 g/mol = d × 0.0821 L.atm/K.mol × 273.15 K

⇒d = 1.70 g/L

okpalawalter8

We have that for the Question "What is the density of fluorine gas, F2, at STP? E) 0.848 g/L B) 1.18 g/ L C ) 1.70 g/L D) 0.589 g/L" it can be said that the density of fluorine gas is

[tex]\rho=1.70g/l[/tex]

Option C

From the question we are told

What is the density of fluorine gas, F2, at STP? E) 0.848 g/L B) 1.18 g/ L C ) 1.70 g/L D) 0.589 g/L

Generally the equation for the density  is mathematically given as

[tex]Density=\frac{P.M}{RT}\\\\\rho=\frac{37.996}{0.0821*273.15}\\\\[/tex]

[tex]\rho=1.70[/tex]

Therefore

the density of fluorine gas is

[tex]\rho=1.70g/l[/tex]

For more information on this visit

https://brainly.com/question/17756498

Other Questions