Answer :
Answer:
Explanation:
Case I: They have same charge.
Charge on each sphere = q
Distance between them, d = 14.8 cm = 0.148 m
Repulsive force, F = 0.235 N
Use Coulomb's law in electrostatics
[tex]F=\frac{Kq_{1}q_{2}}{d^{2}}[/tex]
By substituting the values
[tex]0.235=\frac{9\times10^{9}q^{2}}{0.148^{2}}[/tex]
[tex]q=7.56\times10^{-7}C[/tex]
Thus, the charge on each sphere is [tex]q=7.56\times10^{-7}C[/tex].
Case II:
Charge on first sphere = 4q
Charge on second sphere = q
distance between them, d = 0.148 m
Force between them, F = 0.235 N
Use Coulomb's law in electrostatics
[tex]F=\frac{Kq_{1}q_{2}}{d^{2}}[/tex]
By substituting the values
[tex]0.235=\frac{9\times 10^{9}\times 4q^{2}}{0.148^{2}}[/tex]
[tex]q=3.78\times10^{-7}C[/tex]
Thus, the charge on second sphere is [tex]q=3.78\times10^{-7}C[/tex] and the charge on first sphere is [tex]4q = 4\times 3.78\times 10^{-7}=1.51 \times 10^{-6} C[/tex].