During the first 14 minutes of a 1.0 hour trip, a car has an average speed 36 km/h. What must the average speed in km/h of the car during the rest of the trip be if the car is to have an average speed of 74.0 km/h for the entire trip

Answer :

Answer:

85.5 km/h

Explanation:

[tex]t_{1}[/tex] = time interval for first phase = 14 min = [tex]\frac{14}{60}[/tex] h = 0.233 h

[tex]t_{2}[/tex] = time interval for second phase = 46 min = [tex]\frac{46}{60}[/tex] h = 0.767 h

[tex]v[/tex] = average speed for the entire trip = 74 km/h

[tex]v_{1}[/tex] = average speed in first phase = 36 km/h

[tex]v_{2}[/tex] = average speed in second phase

[tex]d_{1}[/tex] = distance traveled in first phase

[tex]d_{2}[/tex] = distance traveled in first phase

average speed is given as

[tex]v = \frac{d_{1} + d_{2}}{t_{1} + t_{2}}[/tex]

[tex]v = \frac{v_{1} t_{1} + v_{2} t_{2}}{t_{1} + t_{2}}[/tex]

[tex]74 = \frac{(36) (0.233) + v_{2} (0.767)}{0.233 + 0.767}[/tex]

[tex]74 = (36) (0.233) + v_{2} (0.767)[/tex]

[tex]v_{2} = 85.5[/tex] km/h

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