Answer :
Answer:
-6m/s^2
Explanation:
Acceleration is the quantity that increase or decrease the velocity per time unit, that means, we can obtain that quantity by dividing change in velocity between time, in this case a=(Vfinal-Vinitial)/t, replacing a=(0m/s-60m/s)/10s , so a=-6m/s^2.
An airplane traveling at 60 m/s comes to a stop in 10 seconds. The airplane’s acceleration is - 6 m / s^{2}[/tex]
Answer: - 6 m / s^{2}[/tex]
Explanation:
Given that the air plane was travelling at the speed of 60 m/s and the time taken to came to rest was 10 sec. Therefore, the acceleration can be calculated by following method,
Given that velocity = 60 m /s
Time taken to stop t = 10 sec
We can thus know that the final velocity is zero as the air-plane comes to rest, so the given velocity is the initial velocity
Therefore, acceleration or rather in this case,
[tex]\text { deceleration }=\frac{v-u}{t}[/tex]
[tex]a=\frac{60-0}{10}= - 6 m / s^{2}[/tex]