Answer: [tex]\bold{D)\quad \dfrac{1}{27t^{15}}}[/tex] [tex]\bold{C)\quad \dfrac{4y^{10}}{x^2}}[/tex]
Step-by-step explanation:
The negative flips the numerator to the denominator and vice versa.
[tex](3t^5)^{-3}\quad =\dfrac{1}{(3t^5)^{3}}\quad =\dfrac{1}{3^3\cdot t^{5\cdot 3}}\quad =\large\boxed{\dfrac{1}{27t^{15}}}[/tex]
[tex]\bigg(\dfrac{x}{2y^5}\bigg)^{-2}\quad =\bigg(\dfrac{2y^5}{x}\bigg)^2\quad =\dfrac{2^2\cdot y^{5\cdot 2}}{x^2}\quad =\large\boxed{\dfrac{4y^{10}}{x^2}}[/tex]
