What is the equation of the line that is parallel to the line 5x + 2y = 12 and passes through the point (−2, 4)? y = – Five-halvesx – 1 y = – Five-halvesx + 5 y = Two-fifthsx – 1 y = Two-fifthsx + 5

Answer :

Answer:

[tex]y= \frac{-5}{2}x-1[/tex]

Step-by-step explanation:

the line equation is  5x + 2y = 12

Solve for y to find out slope m

y=mx+b

[tex]5x + 2y = 12[/tex]

Subtract 5x from both sides

[tex]2y =-5x+12[/tex]

Divide both sides by 2

[tex]y=\frac{-5}{2} x+6[/tex]

slope = -5/2

Slope of parallel lines are same . So slope of parallel line is [tex]\frac{-5}{2}[/tex]

m=-5/2 , point (-2,4)

[tex]y-y_1= m(x-x_1)[/tex]

[tex]y-4= \frac{-5}{2}(x+2)[/tex]

[tex]y-4= \frac{-5}{2}x-5[/tex]

Add 4 on both sides

[tex]y= \frac{-5}{2}x-1[/tex]

Answer:

Answer is A

Step-by-step explanation:

Trust the process

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