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Acetone must be kept in a​ closed, pressure tank due to evaporation. Acetone evaporates at a rate of 44 grams per minute left bracket StartFraction g Over min EndFraction right bracket g min. If the tank holds 5454 ​pound-mass ​[lbm​] of acetone and is allowed to remain open to the​ atmosphere, how many days​ [d] will it take for half of the acetone to​ evaporate?

Answer :

IthaloAbreu

Answer:

20 days

Explanation:

We know that the rate of evaporation of acetone is 44 g/min, so let's transform the mass in gram

1 lbm = 453.592 g

545 lbm = [tex]\frac{x}{453.592}[/tex]

x = 2,473,893 g

So, half of this mass is 1,236,946.5 g

So, the time of evaporation will be

t = mass/rate of evaporation

t = 1,236,946.5/44

t = 28,112.42 min

One hour has 60 min, so

t = 28,112.42/60 = 468.54 hours

And one day has 24 hours, then

t = 468.54/24

t = 19.5 days

So, it'll be necessary 19 days and a part of another day to evaporate half of the acetone, so it'll be necessary 20 days.

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