Answer :
Answer:
inside dimension [tex]= 142 mm \times 42 mm[/tex]
cross section area [tex]= 7.5\times 10^{-3} m^2[/tex]
mass of 1.2 meter log steel [tex] = 1.843\times 10^{-3} \rho[/tex]
Explanation:
given data:
Outside dimension of steel rectangular [tex]= 150 mm\times 50mm[/tex]
Thickness = 4 mm
Long = 1.22 m
inside dimension will be [tex]= (150- 8)mm \times ( 50-8)mm[/tex]
[tex]= 142 mm \times 42 mm[/tex]
cross section area [tex]= 150\times 50 mm^2[/tex]
[tex]= 7500\times 10^{-6} m^2[/tex]
[tex]= 7.5\times 10^{-3} m^2[/tex]
let the density be assumed as \rho
mass of 1.2 meter log steel will be [tex]= 1.2 \times (7.5\times 10^{-3} - 0.142\times 0.048)\times \rho[/tex]
[tex] = 1.843\times 10^{-3} \rho[/tex]