Let A be as above, consider Ax = b where b = (31, 2, 21, 11). Find x1 using Cramer’s rule. (You may use MATLAB/Octave to compute the determinants, but write out what you are computing.).

Matrix a= 8 6 -3 20

4 2 -5 -7

8 2 7 20

4 2 -11 -4

Answer :

Answer:

x1= 1

Step-by-step explanation:

The Cramer's rule say that x1=[tex]\frac{det(A1)}{det(A)}[/tex] where A1 is the matrix A change the column 1 by the vector b.

Then A1= [tex]\left[\begin{array}{cccc}31&6&-3&20\\2&2&-5&-7\\21&2&7&20\\11& 2&-11&-4\end{array}\right][/tex].

Using Octave we have that  det(A1)=-3840 and det(A)=-3840.

Then x1=[tex]\frac{-3840}{-3840}=1[/tex].

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