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A brick is thrown upward from the top of a building at an angle of 25.7° above the horizontal and with an initial speed of 15.1 m/s. The acceleration of gravity is 9.8 m/s^2 If the brick is in flight for 3.4 s, how tall is the building? Answer in units of m

Answer :

Answer:

the building is 34.408 m tall

Explanation:

given,

initial velocity of brick = 15.1 m/s

at an angle of = 25.7°

vertical component of the velocity

 Vy = 15.1 sin 25.7°            

       = 6.54 m/s                      

we know                                

[tex]s = u t + \dfrac{1}{2} a t^2[/tex]

[tex]s = 6.54\times 3.4 + \dfrac{1}{2}\times -9.8 \times 3.4^2[/tex]

s = -34.408 m

hence, the building is 34.408 m tall .

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