Answer :
Answer:
h/(m*c)
Explanation:
Hi!
Lets denote the units of X as [X]
Since the dimentions of h are:
[tex][h] = \frac{ML^{2}}{T}[/tex]
If we divide [h] by the units of mass, we get:
[tex]\frac{[h]}{[m]} = \frac{L^{2}}{T}}[/tex]
Also we know that:
[tex][c] = \frac{L}{T}[/tex]
So:
[tex][\frac{h}{mc}] = \frac{L^{2}}{T}}*\frac{T}{L}=L[/tex]
Therefore
h/(mc) has dimentiosn of length