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A car travels in a straight line from a position 50 m to your right to a position 210 m to your right in 5 sec. a. What is the average velocity of the car?b. Construct a position vs. time graph and calculate the slope of the line of best fit.

Answer :

Answer:

The average velocity of the car is 32 m/s.

Explanation:

Given that,

Initial position = 50 m

Final position = 210 m

Time = 5 sec

(a). We need to calculate the average velocity of the car

Using formula of average velocity

[tex]v_{avg}=\dfrac{v_{f}-v_{i}}{t}[/tex]

Put the value into the formula

[tex]v_{avg}=\dfrac{210-50}{5}[/tex]

[tex]v_{avg}=32\ m/s[/tex]

(b). We need to draw the position vs. time graph

We need to calculate the slope of the line of best fit.

Using formula of slop

[tex]slope =\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}[/tex]

Put the value into the formula

[tex]slope =\dfrac{210-50}{5-0}[/tex]

[tex]slope =32[/tex]

Hence, The average velocity of the car is 32 m/s.

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