Answer :
Answer:
[tex]97.0\frac{kg}{mol*dL}[/tex]
Step-by-step explanation:
we know that 1 kg is equal to 1000 g and also we know that 1 L is equal to 10 dL then using a conversion factor we have:
[tex]( 9.70\times 10^{5} \dfrac{1}{10000} \frac{kg}{mol*dL} )[/tex]
Now we can eliminate the units of g and L and we have
][tex]( 9.70\times 10^{5} \dfrac{1}{10000} \frac{kg}{mol*dL} )=( 9.70\times 10^{5} \dfrac{1}{1\times 10^{4}} \frac{kg}{mol*dL} )=(\dfrac{9.70\times 10^{5}}{1\times 10^{4}} \frac{kg}{mol*dL} )[/tex]
Using the properties of exponents we have
[tex](\dfrac{9.70\times 10^{5}}{1\times 10^{4}} \frac{kg}{mol*dL} )=9.70\times 10^{1}\frac{kg}{mol*dL}=97.0\frac{kg}{mol*dL}[/tex]