Two rockets are flying in the same direction and are side by side at the instant their retrorockets fire. Rocket A has an initial velocity of +5300 m/s, while rocket B has an initial velocity of +8700 m/s. After a time t both rockets are again side by side, the displacement of each being zero. The acceleration of rocket A is -11 m/s^2. What is the acceleration of rocket B?

Answer :

Answer:[tex]-18.05 m/s^2[/tex]

Explanation:

Given

Initial velocity of rocket A ([tex]v_A[/tex]) 5300m/s

Initial velocity  of rocket B([tex]v_B[/tex]) 8700 m/s

after time t they have displacement=0

[tex]s_A=5300\times t+\frac{1}{2}\times \left ( -11\right )t^2[/tex]

[tex]0=5300\times t+\frac{1}{2}\times \left ( -11\right )t^2[/tex]

[tex]t=\frac{5300\times 2}{11}=963.63 s[/tex]

for Rocket B

[tex]s_B=8700\times t+\frac{1}{2}\times \left ( a_B\right )t^2[/tex]

time is same for A & B

[tex]0=8700\times 963.63+\frac{1}{2}\times \left ( a_B\right )963.63^2[/tex]

[tex]a_B=\frac{2\times 8700}{963.63}=-18.05 m/s^2[/tex]

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