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The driver of a sports car traveling at 10.0⁣m/s steps down hard on the accelerator for 5.0⁣s and the velocity increases to 30.0⁣m/s. What was the average acceleration of the car during the 5.0s time interval?

Answer :

amhugueth

Answer:

[tex]a=4m/s^{2}[/tex]

Explanation:

From the concept of average acceleration we know that

[tex]a=\frac{v_{2}-v_{1} }{t_{2}-t_{1}  }[/tex]

From the exercise we know that

[tex]v_{2}=30m/s\\v_{1}=10m/s\\t_{2}=5s\\t_{1}=0s[/tex]

So, the average acceleration of the car is:

[tex]a=\frac{30m/s-10m/s}{5s}=4m/s^{2}[/tex]

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