Answer :
Answer:51.44 units
Explanation:
Given
x component of vector is [tex]-27.3\hat{i}[/tex]
y component of vector is [tex]43.6\hat{j}[/tex]
so position vector is
[tex]r=-27.3\hat{i}+43.6\hat{j}[/tex]
Magnitude of vector is
[tex]|r|=\sqrt{27.3^2+43.6^2}[/tex]
[tex]|r|=\sqrt{2646.25}[/tex]
|r|=51.44 units
Direction
[tex]tan\theta =\frac{43.6}{-27.3}=-1.597[/tex]
vector is in 2nd quadrant thus
[tex]180-\theta =57.94[/tex]
[tex]\theta =122.06^{\circ}[/tex]