Answer :
Answer:
diameter = 9.951 × [tex]10^{-6}[/tex] m
Explanation:
given data
NA = 0.1
refractive index = 1.465
wavelength = 1.3 μm
to find out
What is the largest core diameter for which the fiber remains single-mode
solution
we know that for single mode v number is
V ≤ 2.405
and v = [tex]\frac{2*\pi *r}{ wavelength} NA[/tex]
here r is radius
so we can say
[tex]\frac{2*\pi *r}{ wavelength} NA[/tex] = 2.405
put here value
[tex]\frac{2*\pi *r}{1.3*10^{-6}} 0.1[/tex] = 2.405
solve it we get r
r = 4.975979 × [tex]x^{-6}[/tex] m
so diameter is = 2 × 4.975979 × [tex]10^{-6}[/tex] m
diameter = 9.951 × [tex]10^{-6}[/tex] m