Answer :
Answer:
The density of nuclear matter is [tex]10^{6}\ Mg/\mu L[/tex]
Explanation:
Given that,
Density [tex]\rho= 10^{18}\ kg/m^3[/tex]
Using unit conversation,
[tex]\Rightarrow \dfrac{10^{18}\ kg}{1\ m^3}\times\dfrac{1 Mg}{10^{6}g}\times\dfrac{1000\ g}{1\ kg}\times\dfrac{1\ m^3}{10^6\ cm^3}\times\dfrac{1\ cm^3}{1\ mL}\times\dfrac{1000\ mL}{1\ L}\times\dfrac{10^{-6}\ L}{1\ \muL}[/tex]
[tex]\Rightarrow \dfrac{10^{18}\times10^{3}\times10^{3}\times10^{-6}}{10^{6}\times10^{6}\times10^{6}}[/tex]
The density of nuclear matter is
[tex]\rho=10^{6}\ Mg/\mu L[/tex]
Hence, The density of nuclear matter is [tex]10^{6}\ Mg/\mu L[/tex]