Answer :
Answer:
The maximum height is 162.67 m.
Explanation:
Suppose the total height is h.
And at the height of 2/3h the speed of an object is,
[tex]u=32.6m/s[/tex]
And the remaining height will be,
[tex]h'=h-\frac{2}{3}h\\ h'=\frac{1}{3}h[/tex]
So, according to question the initial speed is,
[tex]u=32.6m/s[/tex]
Acceleration in the upward direction is negative,
[tex]a=-9.8m/s^{2}[/tex]
And the final speed will be v m/s which is 0 m/s.
Now according to third equation of motion.
[tex]v^{2} =u^{2} -2as[/tex]
Here, v is the final velocity, u is the initial velocity, a is the acceleration, s is the displacement.
[tex]0^{2} =32.6^{2} +2(-9.8)\dfrac{h}{3} \\h=\dfrac{3\times 1062.76}{2\times 9.8}\\h=162.67 m[/tex]
Therefore, the maximum height is 162.67 m.