Answer :

luisejr77

Answer: SECOND OPTION

Step-by-step explanation:

Given the following equation:

[tex]x^2-36=5x[/tex]

You can follow these steps in order to find the values of "x" that makes the equation true:

1. Subtract [tex]5x[/tex] from both sides of the equation:

[tex]x^2-36-5x=5x-5x\\\\x^2-5x-36=0[/tex]

2. Factor the equation. Find two numbers whose sum be -5 and whose product be -36. These are 4 and -9:

[tex](x+4)(x-9)=0[/tex]

Then you get:

[tex]x_1=-4\\\\x_2=9[/tex]

Checking:

[tex](-4)^2-36=5(-4)\\\\-20=-20[/tex]

TRUE

[tex](9)^2-36=5(9)\\\\45=45[/tex]

TRUE

Answer:

Its B. -4 and 9

Step-by-step explanation:

Just took it and got 100%

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