i need to solve for z

Answer:
[tex]C=\frac{5}{9}(F-32)[/tex]
Step-by-step explanation:
we have
[tex]F=\frac{9}{5}C+32[/tex]
Solve for C
That means ----> isolate the variable C
Subtract 32 both sides
[tex]F-32=\frac{9}{5}C+32-32[/tex]
[tex]F-32=\frac{9}{5}C[/tex]
Multiply by 5/9 both sides
[tex]\frac{5}{9}(F-32)=\frac{5}{9}(\frac{9}{5}C)[/tex]
[tex]\frac{5}{9}(F-32)=C[/tex]
Rewrite
[tex]C=\frac{5}{9}(F-32)[/tex]